Tentukan nilai dari ²log²8- ²log2/²log √8-²log√2

²log² 8 = (²log 8)² = 3² = 9
²log 2 = 1
²log√8 = 3/2

p = (²log² 8 - ²log 2 ) = 9-1 = 8
q = ²log√8 - ²log2 = 3/2 – 1 = 1/2

p/q = 8 : (1/2) = 16