Tentukan nilai dari 2³log 4-1/2³log 25+³log 10-³log32 !

  2³log4 – 1/2³log25 + ³log10 – ³log32

= 2³log2² – 1/2³log5² + ³log(5×2) – ³log2⁵

= 2.2³log2 – 1/2.2³log5 + ³log5 + ³log2 – ³log2⁵

= 4³log2 – ³log5 + ³log5 + ³log2 – ³log2⁵

=  ³log2⁴ + ³log2 – ³log2⁵ + ³log5 – ³log5

=  ³log (2⁴ x 2) : 2⁵ + ³log5/5

=  ³log 1 + ³log 1

=  ³log (1 x 1)

=  ³log 1