Tentukan nilai dari 2log6 + 3. 2log4-2log 3=

2log6 + 3.2log4 – 2log3
= 2log6 – 2log3 + 3 . 2log2^2
= 2log(6/3) + 3. 2. 2log2
= 2log2 + 6
= 1 + 6
= 7