Tentukan nilai potong kurva y = x^2 – 5 dan garis y = 2x + 3

Y = x² – 5
y = 2x + 3

y = y
x² – 5 = 2x + 3
x² – 2x – 5 – 3 = 0
x² – 2x – 8 = 0
(x + 2) (x – 4) = 0
x = -2     x = 4

tipot = (-2, -1)   dan   (4,11)
(x = -2)
→ y = 2(-2) + 3
→ y = -1

(x = 4)
→ y = 2(4) + 3
→ y = 11