a. 5 ( a + 1 ) = 10
b. 0,5 ( 4t – 10 ) = -2( t + 5 )
c. 3 ( 2z – 1 ) + 1 = -2 ( 2z + 9 )
d. – ( 4n – 4 ) + 5n = 2n + 8
e. 20 ( 3x + 1 ) = -50 ( 5 – x )
f. 2c – 5 ( c – 1 ) = 7 – 2c
tolong jawab ya kak dengan caranya
Tentukan nilai variabel dari persamaan persamaan berikut :
Jawaban:
a) a = 1
b) t = -5/4
c) z = – 1,6
d) n = -4
e) c = -6
Penjelasan dengan langkah-langkah:
a) 5 ( a + 1 ) = 10
5a + 5 = 10
5a = 10 – 5
5a = 5
a = 5/5
a = 1
b) 0,5 ( 4t – 10 ) = -2( t + 5 )
0,5 = 1/2
1/2 ( 4t – 10 ) = -2( t + 5 )
4/2 t – 10/2 = -2t + ( -10)
2t – 5 = -2t – 10
2t + 2t = -10 + 5
4t = -5
t = -5/4
c) 3 ( 2z – 1 ) + 1 = -2 ( 2z + 9 )
(6z -3) + 1 = -4z + (-18)
6z – 3 + 1 = -4z – 18
6z – 2 = -4z – 18
6z+ 4z = -18 + 2
10z = – 16
z = – 16 / 10
z = – 1,6
d) – ( 4n – 4 ) + 5n = 2n + 8
(-4n + 4) + 5n = 2n + 8
-4n + 4 + 5n = 2n + 8
-4n + 5n – 2n = 8 – 4
-6n + 5n = 4
-n = 4
n = -4
e) 20 ( 3x + 1 ) = -50 ( 5 – x )
(60x + 20) = -250 + 50x
60x + 20 = -250 + 50x
60x – 50x = -250 – 20
10x = -270
x = -27
f) 2c – 5 ( c – 1 ) = 7 – 2c
2c – (5c – 1) = 7 – 2c
2c – 5c + 1 = 7 – 2c
2c + 2c – 5c = 7 – 1
-c = 6
c = -6