tolong kaka^^
Tentukan nilai x
2^1200 + 4^600 + 8^400 + 16^800 = 2^x
2^1200 + 2^1200 + 2^1200 + 2^3200 = 2^x
2^1200 + 2^1200 + 2^1200 + (2^1200.2^1200.2^800) = 2^x
3.2^1200 + (2^1200)² .2^800 = 2^x
2^1200 (3+2^1200.2^800) = 2^x
2^1200 (3 + 2^800.2^400.2^800) = 2^x
2^800.2^400 (3 + (2^800)².2^400) = 2^x
2^800.2^400 ((3 + 2^800) = 2^x
2^400.2^400.2^400(3 + 2^400.2^400) = 2^x
((2^400)²(3.2^400 + 1) = 2^x
2^400(3.2^400 + 2^400) = 2^x
2^400((2^400(3+1) = 2^x
2^400(2^400(4) = 2^x
2^400(2^402) = 2^x
2^(400+402) = 2^x
2^802 = 2^x
x = 802