Tentukan nilai x yang memenuhi persamaan ²log²(2x-2) – ²log(2x-2)⁵ = -4​

logaritma

²log² (2x – 2) – ²log (2x – 5) = -4

²log² (2x – 2) – 5 ²log (2x – 5) + 4 = 0

a² – 5a + 4 = 0

(a – 1)(a – 4) = 0

a = 1 atau a = 4

utk a = 1

a = 1

²log (2x – 2) = 1

2x – 2 = 2¹

x = (2 + 2)/2

x = 2

utk a = 4

²log (2x – 2) = 4

2x – 2 = 2⁴

x = (16 + 2)/2

x = 9

Nilai x yang memenuhi :

2 dan 9