Tentukan nilai z dari

Jawaban:

-6

Penjelasan dengan langkah-langkah:

i. x+y+z=3

ii. 3y-z=21

iii. 2x+y+3z=-5

eliminasi

i. x+y+z=3

ii. 3y-z=21

———— +

x+4y= 24……….iv

iii .2x + y + 3z = -5 (×1) 2x + y + 3z = -5

i. x + y + z = 3 (×3) 3x + 3y + 3z = 9

———————– –

-x-2y= -14 .,……..v

iv. x+4y= 24

v. -x-2y= -14

————— +

2y= 10

y= 5

distribusi

3y-z = 21

15-z = 21

-z. = 21-15

-z = 6

z = -6

2x+y+3z= -5

2x + 5+ 3(-6)= -5

2x + 5- 18= -5

2x= -5+13

2x= 8

x = 4

hp :{ 4,5,-6}

jadi nilai z = -6