Tentukan nilait
5log (t-2) + 5log (2t+1) = 2
Jawaban Terkonfirmasi
⁵log((t-2)(2t+1))=⁵log5²
2t²+t-4t-2=25
2t²-3t-27=0
(2t-9)(t+3)=0
t=9/2 atau t=-3
Tentukan nilait
5log (t-2) + 5log (2t+1) = 2
⁵log((t-2)(2t+1))=⁵log5²
2t²+t-4t-2=25
2t²-3t-27=0
(2t-9)(t+3)=0
t=9/2 atau t=-3