Tentukan penyelesaian persamaan”” berikut dengan cara pemfaktoran

1) x²+8x=0 => x(x+8)=0

x=0 dan x+8= 0

x = -8

{-8,0}

2) 7x²-21x=0 => 7x (x-3) = 0

= x (x – 3) = 0

x=0 dan x-3=0

x = 3

{0,3}

3) y²-64=0 => y² = 64

. y = ± 8

. y = 8 dan y= -8

. {-8,8}

4) 9y² – 49 = 0

=> 9y² = 49

y² = 49/9

y = ±7/3

y = -7/3 dan y = 7/3

{-7/3,7/3}

5) x²-5x-24=0

= x²+3x-8x-24=0

= x(x+3)-8(x+3)=0

= (x+3) (x-8) =0

= x+3=0 dan x-8=0

x=-3 x= 8

{-3,8}

6) x² – 16x + 15

= x²-x-15x+15=0

= x(x-1)-15(x-1)=0

= (x-1) (x-15) = 0

x=1 dan x = 15

{1,15}

7) 2x² + 3x – 35 = 0

= 2x²+10x-7x-35=0

= 2x(x+5)-7x-35=0

= 2x(x+5)-7(x+5)=0

= (x+5) (2x-7)

= x = -5. dan 2x-7=0 => 2x=7 =>x=7/2

{-5,7/2}

8) 6y²+7y-20=0

= 6y²+15y-8y-20=0

= 3y(2y+5)-8y-20=0

= 3y(2y+5)-4(2y+5)=0

= (2y+5)=0 (3y-4) =0

= 2y+5=0 3y-4 = 0

2y = -5 3y = 4

y= -5/2 y = 4/3

{-5/2, 4/3}

maaf kalo ada yg salah,

semoga membantu