Tentukan penyelesaian SPLDV, 5x + 2y = 3 dan 3x – 2y = -11 dengan metode eliminasi!​

Jawaban:

3x-2y = 4 |×1|

2x+y = 5 |×2|

=>3x-2y = 4

4x+2y = 10

———————- +

7x = 14

x = 2

=> 2x + y = 5

2.2+y = 5

4 + y = 5

y = 1

HP = {2,1}

b. 3x+2y = 12 |×1|

4x+y = 1 |×2|

=>3x+2y = 12

8x+2y = 2

—————- –

-5x = 10

x = -2

=> 4x + y = 1

4(-2) + y = 1

(-8) + y = 1

y = 9

HP = {-2,9}

c. 5x-3y = 8 |×2|

2x+5y = -3 |×5|

=>10x-6y = 16

10x+25y = -15

——————— –

-31y = 31

y = -1

=>5x – 3y = 8

5x – 3(-1) = 8

5x + 4 = 8

5x = 4

x = 4/5

HP ={4/5,-1}

Semoga jawabannya bener ya

Penjelasan dengan langkah-langkah:

Terima kasih

Jawab:

hp : { -1 , 4 }

Penjelasan dengan langkah-langkah: