1.) x+7 = 5x+15
2.) 2y-8 = 3y-20
3.) a+6 = 2a+8
4.) 3b-12 = b+4
5.) 7c+35 = 2c-5
Tentukan penyelsaian dari persamaan linier berikut!
1.x+7=5x+15
7-15=5x-x
-8=4x
x=-2
2. 2y-8=3y-20
-8+20=3y-2y
12=y
y=12
3 .a+6=2a+8
6-8=2a-a
-2=a
a=-2
4.3b-12=b+4
-12-4=b-3b
-16=-2b
b=-16/-2
b=8
5 7c+35=2c-5
35+5=2c-7c
40=-5c
c=40/-5
c=-8
1. x + 7 = 5x + 15
x – 5x = 15 – 7
-4x = 8
x = -2
2. 2y – 8 = 3y – 20
2y – 3y = -20 + 8
-y = -12
y = 12
3. a + 6 = 2a + 8
a – 2a = 8 – 6
-a = 2
a = -2
4. 3b – 12 = b + 4
3b – b = 4 + 12
2b = 16
b = 8
5. 7c + 35 = 2c – 5
7c – 2c = -5 – 35
5c = -40
c = -8
semoga membantu…