Tentukan persamaan garis singgung kurva
Y=2x³-3x²-4x+5 dititik yang berbasis 2
~ PGS
y = f(x) = 2x³ – 3x² – 4x + 5
m = f'(x) = 6x² – 6x – 4
m = f'(2) = 6(2)² – 6(2) – 4
m = f'(2) = 24 – 12 – 4
m = f'(2) = 8
y = f(2) = 2(2)³ – 3(2)² – 4(2) + 5
y = f(2) = 16 – 12 – 8 + 5
y = f(2) = 1
Maka , diperoleh PGS :
y – b = m(x – a)
y – 1 = 8(x – 2)
y – 1 = 8x – 16
y = 8x – 15