Tentukan persamaan garis singgung kurva Y=2x³-3x²-4x+5 dititik yang berbasis 2

~ PGS

y = f(x) = 2x³ – 3x² – 4x + 5

m = f'(x) = 6x² – 6x – 4

m = f'(2) = 6(2)² – 6(2) – 4

m = f'(2) = 24 – 12 – 4

m = f'(2) = 8

y = f(2) = 2(2)³ – 3(2)² – 4(2) + 5

y = f(2) = 16 – 12 – 8 + 5

y = f(2) = 1

Maka , diperoleh PGS :

y – b = m(x – a)

y – 1 = 8(x – 2)

y – 1 = 8x – 16

y = 8x – 15