Tentukan persamaan garis yang melalui titik ( 2, -5 ) dan ( -6, 3 ) !​

Materi : Persamaan Garis Lurus

Titik ( x¹ = 2 dan y¹ = -5 )

Titik ( x² = -6 dan y² = 3 )

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y – y¹ / y² – y¹ = x – x¹ / x² – x¹

( y + 5 )/( 3 – 5 ) = ( x – 2 )/( – 6 – 2 )

( y + 5 )/(-2) = ( x – 2 )/(-8)

-8( y + 5 ) = -2( x – 2 )

– 8y – 40 = – 2x + 4

8y – 2x + 44 = 0

4y – x + 22 = 0

Semoga bisa membantu

(y – y1)/(y2 – y1) = (x – x1)/(x2 – x1)

(y – (-5))/(3 – (-5)) = (x – 2)/(-6 – 2)

(y + 5)/8 = (x – 2)/(-8)

-8y – 40 = 8x – 16

-8y = 8x + 24

-y = x + 3

y = 3 – x

tolong dicek ya barangkali salah