Tentukan persamaan garis yang melalui titik (6,-7) dan sejajar garis x – 2y =6

Kelas 8 Matematika
Bab Persamaan Garis

ax + by = c, sejajar, (p, q)
ax + by = ap + bq

x – 2y = 6, sejajar, (6, -7)
x – 2y = 1 . 6 – 2 . (-7)
x – 2y = 6 + 14
x – 2y = 20

X – 2y = 6
m1 = -a/b = -1/-2 = ½
Karena garis 1 // garis 2 maka m2 = ½
y – y1 = m (x – x1)
y – -7 = ½ (x – 6)
y + 7 = ½x – 3
2y + 14 = x – 6
2y = x – 6 – 14
2y = x – 20
-x + 2y + 20 = 0