Tentukan persamaan garis yang melalui titik p(1,-3) dan Q(3,-2)

Jawab :

m : y2 – y1/ x2 – x1 = (-2) – (-3)/ 3 – 1 = 1/2

y – y1 = m(x – x1)
y – (-3) = 1/2(x – 1)
y + 3 = 1/2(x – 1)
y + 3 = 1/2x – 1/2 x 1
y + 3 = 1/2x – 1/2
_________________ x 2
2 . y + 3 . 2 = 1/2x . 2 – 1/2 . 2

2y + 6 = 1x – 1
2y + 6 – x + 1 = 0
2y – x + 7 = 0

M = y2 – y1 / x2 – x1
= -2 – -3 / 3 – 1
= -2 + 3 / 2
= ½
y – y1 = m (x – x1)
y – -3 = ½ (x – 1)
y + 3 = ½x – ½
2y + 6 = x – 1
2y = x – 1 – 6
2y = x – 7
-x + 2y – 7 = 0