Tentukan persamaan garis yang tegak lurus 2y+2=-7per4(x-7)dan melalui titik (-2,-3)

PGL

2y + 2 = -7/4(x – 7)

8y + 8 = -7x + 49

7x + 8y – 41 = 0

m = -koef x / koef y

m = -7/8

Agar Tegak Lurus :

m₂ = -1 / m₁

m₂ = 8/7

Maka PGL baru :

y – y₁ = m(x – x₁)

y + 3 = 8/7(x + 2)

7y + 21 = 8x + 16

8x – 7y – 5 = 0