Tentukan persamaan garis yg tegak lurus garis 2×-3y=4 dan melalui titik (1,3)

3y = – 2x + 4
y = (-2/3)x + 4/3
m1 = – 2/3
m2 = 3/2

y – 3 = (3/2)(x – 1)
2y – 6 = 3x – 3
3x – 2y + 3 = 0