Tentukan pH dari larutan CH3COOH 0.05 M (Ka = 10^-5)
Jawaban Terkonfirmasi
[H+] = √(Ka x Masam)
= √ (10^-5 x 0,05) = (1/2)^1/2 x 10^-3
pH = -log [H+] = 3 – 1/2 log (1/2)
pH = 3 + 1/2 log 2
Semoga membantu.
Tentukan pH dari larutan CH3COOH 0.05 M (Ka = 10^-5)
[H+] = √(Ka x Masam)
= √ (10^-5 x 0,05) = (1/2)^1/2 x 10^-3
pH = -log [H+] = 3 – 1/2 log (1/2)
pH = 3 + 1/2 log 2
Semoga membantu.