Tentukan PH laruran H2SO4 0,0002M
Jawaban Terkonfirmasi
[H+] = M x valensi
[H+] = 0,0002 x 2 = 4 x 10^-4 M
—
pH = -log[H+] = -log(4 x 10^-4) = 4 – log4
Tentukan PH laruran H2SO4 0,0002M
[H+] = M x valensi
[H+] = 0,0002 x 2 = 4 x 10^-4 M
—
pH = -log[H+] = -log(4 x 10^-4) = 4 – log4