Tentukan pH larutan NH, 0,02 M (kb=2×10-5) ​

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Tentukan pH larutan NH, 0,02 M (kb=2×10-5) ​

pH = 5,5

Penjelasan:

• M = 2 . 10^-2

• Kb = 2 . 10^-5

Pkb = – log Kb

= – log 2 . 10^-5

= 5 – log 2

= 5 – 0,3

= 4,7

pH = 1/2 (14 – Pkb – log M garam)

= 1/2 (14 – 4,7 – log 2 . 10^-2)

= 1/2 (14 – 4,7 – (-2 log 2)

= 1/2 (14 – 4,7 + 2 – log 2)

= 1/2 (14 – 4,7 + 2 – 0,3)

= 1/2 (11)

= 5,5

Semoga membantu, maaf klu ada kesalahan…