Tentukan S6 dan S8 dari deret geometri berikut :

A.S6=a(1-r^n)/1-r
=8(1-1/2^6)/1-1/2
=8(1-1/64)/(1/2)
=8(64/64-1/64)/(1/2)
=8(63/64)/(1/2)
=(63/8)/(1/2)
=(63/8)x2/1
=126/8
=15 6/8=15 3/4
S8 =a(1-r^n)/1-r
=8(1-1/2^8)/1-1/2
=8(1-1/256)/(1/2)
=8(256/256-1/256)/(1/2)
=8(255/256)/(1/2)
=(255/32)/(1/2)
=(255/32)x(2/1)
=510/32
=15 30/32=15 15/16
b.S6=a(r^n-1)/r-1
=2(2^6-1)/2-1
=2(64-1)/1
=2(63)/1
=126
S8=a(r^n-1)/r-1
=2(2^8-1)/2-1
=2(256-1)/1
=2(255)
=510
c.S6=a(1-r^n)/1-r
=3,1(1-0.1^6)/1-0.1
=3,1(1-0,000001)/0.9
=3,1(0.999999)/0,9
=3,099999/0,9
=3,44
S8=a(1-r^n)/1-r
=3,1(1-0,1^8)/1-0,1
=3,1(1-0,00000001)/0,9
=3,1(0,99999999)/0,9
=3,099999969/0,9
=3,44
Demikian semoga bermanfaat.