Tentukan volume berikut mtk sd hal 111

Tentukan volume berikut mtk sd hal 111

Jawaban:

8. 3663,33 cm³.

9. 3798,7 cm³.

10. 10466,66 cm³.

Penjelasan dengan langkah-langkah:

8.) V.1 = volume setengah bola

$= frac{1}{2} times frac{4}{3} times pi times {r}^{3} \ = frac{1}{2} times frac{4}{3} times 3.14 times 10 times 10 times 10 \ = frac{2}{3} times 3.140 \ = 2093.33$

V.2 = volume kerucut

$= frac{1}{3} times : pi times {r}^{2} times t \ = frac{1}{3} times 3.14 times 10 times 10 times 15 \ = 3.14 times 5 = 1.570$

V.gabubungan =

= V.1 + V.2

= 2093,33 + 1.570

= 3663,33 cm³.

9.) V.1 = luas setengah bola

$= frac{1}{2} times binom{4}{3} pi {r}^{3} \ = frac{2}{3} times frac{22}{7} times 7 times 7 times 7 \ = 718.7$

V.2 = luas tabung

$= pi times {r}^{2} times t \ = frac{22}{7} times 7 times 7 times 20 \ = 3.080$

V.gabungan

= 718,7 + 3.080

= 3798,7 cm³.

10.) r = 20 : 2 = 10 cm

t = 49 – 20 = 20 cm

V.1 = volume tabung

$pi times {r}^{2} times t \ = 3.14 times 10 times 10 times 20 \ = 6.280$

V.2 = volume bola

$= frac{4}{3} times pi times {r}^{3} \ = frac{4}{3} times 3.14 times 10 times 10 times 10 \ = frac{4}{3} times 3.140 \ = 4186.66$

V.gabungan

= V.1 + V.2

= 6.280 + 4186,66

= 10466,66 cm³.

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KATEGORI:

mapel: matematika.

bab: bangun ruang.

kelas: 6 SD.

Gambar Jawaban