Tentukan X Dari7^³Logx=1

Tentukan X Dari7^³Logx=1

Log(x+7)+log(x+6)-log(x+10)=0
$log frac{(x + 7)(x + 6)}{(x + 10)} = log : 1 \ frac{(x + 7)(x + 6)}{(x + 10)} = 1 \ (x + 7)(x + 6) = (x + 10) \ {x}^{2} + 13x + 42 = x + 10 \ {x}^{2} + 13x - x + 42 - 10 = \ {x}^{2} + 12x + 32 = 0 \ (x + 4)(x + 8) = 0 \ x = - 4 : atau : x = - 8$