Titik balik fungsi kuadrat

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Titik balik fungsi kuadrat

Titik balik fungsi kuadrat

Soal ginian diketika aja dik…
y = x² – 4x + 5
x = -b/(2a) = -(-4)/(2(1)) = 2
substiusi pd y
y = 2² – 4(2) + 5 = 1
tiik (2, 1)