Titik yang terletak pada garis 2x – 3y + 5 = 0 adalah…​

Jawaban:

f(0) = 3y = 2x + 5 –––––> y = ( 2x + 5 ) / 3

= 5/3

f(1) = = 7/3

f(2) = = 9/3

f(x) = 0 –––––––––––––––> 2x = 3y – 5

x = ( 3y – 5 ) / 2

x = –5/2

f(x) = 1 x = –1

f (x) = 2 x = 1/2

jadi titik yg terletak pd garis 2x–3y+5=0

adalah: ( 0, 5/3 ) dan ( –5/2 , 0 )