Tolong ada yang bisa spltv kelas x ini matematika no. 19

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Tolong ada yang bisa spltv kelas x ini matematika no. 19

Tolong ada yang bisa spltv kelas x ini matematika no. 19

Jawab: 0.25629113434

Penjelasan dengan langkah-langkah:

frac{1}{x} + frac{1}{y} - frac{1}{z} = -16

frac{2}{x} - frac{3}{y} - frac{4}{z} = -11

frac{3}{x} + frac{2}{y} - frac{1}{z} = -6

ubah variabel

frac{1}{x} = a , frac{1}{y} = b,frac{1}{z} = c

a + b – c = -16 ————- (1)

2a – 3b – 4c = -11 ————- (2)

3a + 2b – c = -6 ————- (3)

1 dan 3

a + b – c = -16

3a + 2b – c = -6

————————–  -

-2a -b = -10

2a + b = 10

1 dan 2

a + b – c = -16              |x4

2a – 3b – 4c = -11

————————–  -

4a + 4b – 4c = -64              

2a – 3b – 4c = -11

————————–  -

2a +7b = -53

2a +7b = -53

2a + b = 10

——————–   –

6b = -63

b =- frac{63}{6}

b =- frac{21}{2}

2a + b = 10

2a - frac{21}{2} = 10

2a = 10+ frac{21}{2}

2a = frac{20}{2}+ frac{21}{2}

a = frac{41}{4}

3a + 2b – c = -6

frac{123}{4} -21 – c = -6

frac{123}{4} -21 +6 = c

frac{123}{4} -15 = c

frac{123}{4}-frac{60}{4} = 4c

frac{63}{4} = 4c

frac{63}{16} = c

tentukan nilai x,y,z

a = frac{41}{4}

frac{1}{x} = frac{41}{4}

x = frac{4}{41}

b =- frac{21}{2}

frac{1}{y} = -frac{21}{2}

y = -frac{2}{21}

c =frac{63}{16}

frac{1}{z} =frac{63}{16}

z = frac{16}{63}

x + y + z =

frac{4}{41}-frac{2}{21}+frac{16}{63}   /maaf mager hitung pecahan. jadi pk kalku

=0.25629113434