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Jawab
4.
lim(x->2) { 2- √(x+2)}{2 + √(x +2)} / (x-2){2 + √(x+2)}
= (4 -(x +2))/ (x- 2)( 2 + √(x +2))
= -(x – 2) / (x – 2)(2 + √(x+2)
= – 1/(2 + √(x+2)
= – 1/ (2 +√4)
= – 1/4

5.
lim(x->0)  8x { √(4 +6x) + √(4 – 4x)} / {√(4 +6x) – √(4-4x)}{√(4 +6x ) + √(4 – 4x)}
= 8x{√(4+6x) +√(4-4x)} / (4+6x) -(4-4x)
= 8x{√(4+6x) + √(4-4x) / (10x
= 8{√(4+6x)+ √(4-4x)/ (10)
= 8{√4+ √4)}/ 10
= 8(4)/10
= 32/10
= 3,2