Tolong Bantu Dong ka jangan Ngasal​

cari [H+] dulu..

[H+] = √( Ka x Ma)

[H+] = √(10^-6 x 0,01)

[H+] = √(10^-6 x 10^-2)

[H+] = √(10^-8)

[H+] = 10^-4

pH = -log [H+]

pH = – log 10^-4

pH = -4 x – log 10

pH = -4 x -1

pH = 4