Tolong Bantu Jawab !!! dengan carannya ​

y = x² + 4x – 5

a) titik potong sumbu x, syarat y = 0

x² + 4x – 5 = 0

(x+5)(x-1) = 0

x = -5 atau x = 1

HP = {-5, 0} atau {1, 0}

b) titik potong smbu y, syarat x = 0

y = -5

HP = {0, -5}

c) ax² + bx + c = y

sumbu simetris, x = -b/2a

x = -4/2(1) = -2

d) nilai optimum = (-b/2a, – (b²-4ac)/4a)

-b/2a = -4/2(1) = -2

-(b²-4ac)/4a = -(4²-4(1)(-5))/ 4(1) = – (16+20)/4 = -(36/4) = -9

nilai optimum = {-2, -9}

e) koordinat titik puncak = nilai optimum

koordinat titik puncak = {-2, -9}

f) lihat lampiran