Tolong bantu jawab dong

Tolong bantu jawab dong

Jawaban:

Penjelasan dengan langkah-langkah:

$sflim _ { x rightarrow 2 }(2x + 2) \$

$sf2(2) + 2$

$sf4 + 2$

$sf = 6$

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$sflim _ { x rightarrow 3 } frac{ {x}^{2} - 9 }{x - 3}$

$sflim _ { x rightarrow 3 } frac{(x - 3)(x + 3)}{x - 3} \$

$sf3 + 3$

$sf = 6$

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$sflim _ { x rightarrow 2 }(2 {x}^{2} - 4x - 1) \ sf2(2) ^{2} - 4(2) - 1 \ sf2(4) - 8 - 1 \ sf8 - 8 - 1 \ sf0 - 1 \ sf = - 1$

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$sflim _ { x rightarrow 2 } frac{x - 16}{x - 4} \$

$sf frac{2 - 16 }{2 - 4}$

$sf frac{ - 14}{ - 2}$

$sf = 7$