Tolong bantu jawab kak pake caranya

Tolong bantu jawab kak pake caranya

Nomor 1

$a. : {2}^{x - 1} = 8 \ {2}^{x - 1} = {2}^{3} \ x - 1 = 3 \ x = 3 + 1 \ x = 4$

$b. : {5}^{ {x}^{2} - 1} = 125 \ {5}^{ {x}^{2} - 1 } = {5}^{3} \ {x}^{2} - 1 = 3 \ {x}^{2} = 3 + 1 \ {x}^{2} = 4 \ x = sqrt{4} \ x = 2$

$c. : {2}^{3x + 1} = {16}^{x - 2} \ {2}^{3x + 1} = {2}^{4(x - 2)} \ 3x + 1 = 4(x - 2) \ 3x + 1 = 4x - 8 \ 3x - 4x = - 8 - 1 \ - x = - 9 \ x = 9$

Nomor 2

$a. : {(2x - 3)}^{x + 1} = {(2x - 3)}^{ {x}^{2} + x - 3 } \ x + 1 = {x}^{2} + x - 3 \ {x}^{2} + x - 3 - (x + 1) = 0 \ {x}^{2} - 4 = 0 \ {x}^{2} = 4 \ x = sqrt{4} \ x = 2$

$b. : {(2x + 3)}^{x - 1} = {(x + 1)}^{x - 1} \ 2x + 3 = x + 1 \ 2x - x = 1 - 3 \ x = - 2$

Maaf, hanya bisa bantu nomor 1 dan 2