Tolong bantu jawab pake cara​

∫ (2x + 3) / √(3x² + 9x – 1) dx = …

<=>

Dimisalkan :

u = 3x² + 9x – 1

du/dx = 6x + 9

dx = du / 3(2x + 3)

<=>

∫ (2x + 3) / √(3x² + 9x – 1) dx

= ∫ ( (2x + 3) / u^½ ) ( du / 3(2x + 3) )

= ⅓ ∫ u^[-½] du

= ⅓.(1/½).u^½ + C

= ⅔√u + C

= ⅔√(3x² + 9x – 1) + C

Jawaban : ( C )