Tolong Bantu Jawab Pliss.

Tolong Bantu Jawab Pliss.

Ex. $sf angle~URN=beta$

So :

$sf a_{RUN}=frac{beta}{360}times pitimes 5^2$

$sf to purple{a_{RUN}=frac{25beta pi}{360}}$

And :

$sf a_{RAT}=frac{beta}{360}times pitimes 3^2$

$sf to purple{a_{RAT}=frac{9beta pi}{360}}$

So that :

$sf a_{shaded}=a_{RUN}-a_{RAT}=frac{25beta pi}{360}-frac{9beta pi}{360}$

$sf to purple{a_{shaded}=frac{16beta pi}{360}}$

So that :

$sf a_{shaded}~:~a_{RUN}=frac{16beta pi}{360}~:~frac{25beta pi}{360}$

$boxed{boxed{red{huge{begin{array}{ccc}sf a_{shaded}~:~a_{RUN}=\sf 16~:~25red{}end{array}}}}}$