Tolong bantu jawab ya

Tolong bantu jawab ya

Jawab:

Penjelasan dengan langkah-langkah:

$intlimits^3_1 {4x-2} , dx\ =frac{1}{1+1} 4x^{1+1} -2xleft { {3} atop {1}} right.\ =frac{4}{2}x^{2} -2x left { {3} atop {1}} right.\=2x^{2} -2x left { {3} atop {1}} right.\ =(2(3)^2-2(3))-(2(1)^2-2(1))\ =(18-6)-(2-2)\ =12-0\ =12$

$intlimits^1_ {-1} , (x^{2} +2x+3) dx\ =frac{1}{2+1}x^{2+1}+frac{1}{1+1}2x^{1+1}+3xleft { {{1} atop {-1}} right.\ =frac{1}{3}x^{3}+x^{2} +3x left { {{1} atop {-1}} right.\ \ =(frac{1}{3}(1)^{3}+(1)^{2} +3(1))-(frac{1}{3}(-1)^{3}+(-1)^{2} +3(-1))\\ =(frac{1}{3}+1+3)-(frac{-1}{3}+1-3)\ \ =frac{1}{3}+4+frac{1}{3}+2\\ =frac{2}{3}+6\\ =frac{2}{3}+frac{18}{3}\\ =frac{20}{3}$

semoga dapat dipahami, jika kurang dipahami silahkan berkomentar