Tolong bantu jawab ya guys​

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Tolong bantu jawab ya guys​

Tolong bantu jawab ya guys​

Jawab:

limiit

1. lim x-> 4  2x² –  3x + 1

=  2(4)² -4(4) + 1

=  32 – 16 + 1

=  17

2. lim x-> 2   (x- 1) /(x -3)

= (2 – 1)/(2- 3)

= 1/-1

= – 1

3.  lim x -> 5   √(x – 1)

= √(5- 1)

= √4

= 2

4. lim x-> 9  √x + 1

= √9 + 1

=  3 + 1

= 4

5. lim x->4   sqrt[3]{x^2-9}

= sqrt[3]{16-9}

= sqrt[3]{7}