Tolong bantu jawab ya kak

Tolong bantu jawab ya kak

Jawaban:

syarat :

x-3 = 0

x ≠ 3

cara :

$frac{12}{x - 3} > x + 1 \ 12 > (x + 1)(x - 3) \ 12 > x {}^{2} - 2x - 3 \ x {}^{2} - 2x - 3 < 12 \ x {}^{2} - 2x - 3 - 12 < 0 \ x {}^{2} - 2x - 15 < 0 \ (x + 3)(x - 5) < 0 \ x + 3 = 0 \ x1 = - 3 \ x - 5 = 0 \ x2 = 5$

Mungkin seperti itu..

Mohon maaf kalau salah..

Gambar Jawaban