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~> 1/Rp(AB) = 1/4 + 1/8 + 1/8

= 1/4 + 1/4

= 2/4

Rp(AB) = 2 Ω ✓

v(AB) = I.Rp(AB)

= 8.2 ~ 16 V ✓✓

~> – Tinjau loop 1!

Σε + ΣI.R = 0 (sistem rangkaian tertutup)

– ε + ε1 + I1.R1 = 0

I1 = (ε – ε1)/R1

= (24 – 8)/2

= 16/2 ~ 8 A ✓

– Tinjau loop 1!

Σε + ΣI.R = 0 (sistem rangkaian tertutup)

– ε2 + ε1 + I1.R1 + I2.R2 = 0

I2 = (ε2 – ε1 – I1.R1)/R2

= (5 – 8 – 8.2)/7

= (5 – 8 – 16)/7

= -19/7 ~ -2,714 A (tanda -/negatif menandakan jika arah rambat arus listrik pda rangkaian 2 berlawanan dgn tinjauan arah loop 2 yg dimulai dari kutub -/negatif) ✓✓