Tolong bantu no.2 sama 3caranya gimana?​

2.)

Determinan matriks = a.d – b.c

(x – 1).(-1) – 3.2 = 4

-x + 1 – 6 = 4

-x – 5 = 4

-x = 4 + 5

-x = 9

x = -9 —> jawabannya A

3.)

x.(x + 2) – (-5).(-2) = -7

x^2 + 2x – 10 + 7 = 0

x^2 + 2x – 3 = 0

(x + 3).(x – 1) = 0

Maka,

x1 + 3 = 0

x1 = -3

Atau

x2 – 1 = 0

x2 = 1

Sehingga

x1^2 + x2^2

= (-3)^2 + (1)^2

= 9 + 1

= 10 —> jawabannya E

Boleh dong tekan tanda ❤️❤️❤️❤️