Tolong bantu soal ttg limit​

Penjelasan dengan langkah-langkah:

2. Lim x—>0 x-2 × 3+√4x+1

3–√4x+1 3+√4x+1

= (x-2) 3+√4x+1

(9–4x–1)

= (x-2)(3+√4x+1)

–4(x-2)

coret x-2

maka sisa (3+√4x+1)

–4

maka subtitusi x=0

(3+1)

–4

= –1 ✓

3. Lim x—> 9 x-9 × √x+3

√x –3 √x+3

= (x-9)(√x+3)

(x-9)

= √x + 3

= √9 + 3 = 6 ✓

4. Lim x—> 3 x-√2x+3 × x+√2x+3

9–x² x+√2x+3

= (x²–2x–3)

–(x-3)(x+3)(x+√2x+3)

= (x-3)(x+1)

–(x-3)(x+3)(x+√2x+3)

= (x+1)

(-x-3)(x+√2x+3

= 4

–6×6

= –4/36= –1/9 ✓