Tolong bantu ya kak:)))

Tolong bantu ya kak:)))

$lim_{x to 2} frac{x^4-4x^3+16}{x^3-8} \= lim_{x to 2} frac{(x-2)(x^3-2x^2-4x-8)}{(x-2)(x^2+2x+4)} \= lim_{x to 2} frac{x^3-2x^2-4x-8}{x^2+2x+4} \= frac{2^3-2(2)^2-4(2)-8}{2^2+2(2)+4} \= frac{8 - 8 - 8 - 8}{4 + 4 + 4} \= frac{-16}{12} \= frac{-4}{3}$

Jawaban: A. -4/3

Semoga membantu 🙂