Tolong bantu ya kak mau dikumpul​

~> V(t) = ΣVi + ΣVj

= (Vo.cos 53°)i + (Vo.sin 53° ± g.dt)j

= (100.0,6)i + (100.0,8 ± 10dt)j

= [60i + (80 ± 10dt)j] m/s ✓✓

~> S(t) = ΣSi + ΣSj

= (Vo.cos 53°.dt)i + (yo + Vo.sin 53°.dt ± 0,5g.dt²)j

= (100.0,6t)i + (10 + 100.0,8dt ± 5dt²)j

= [(60t)i + (± 5dt + 80dt + 10)j] m ✓✓

~> t(Ym) = Vo.sin 53°/g

= 10.0,8 ~ 8 detik ✓✓

~> Ym = yo + (Vo².sin²53°/2g)

= 10 + (1000.0,64/2) ~ 330 m thdp acuan permukaan tanah pda sumbu vertikal ✓ X[t(Ym)] = Vo.cos 53°.t(Ym)

= 60.8 ~ 480 m thdp thdp acuan permukaan tanah pda sumbu horisontal ✓

(X[t(Ym)] , Ym) = (480 m , 330 m) ✓✓

~> Xm = Vo².sin (2.53°)/g

= 1000.0,961 ~ 961 m thdp acuan permukaan tanah pda sumbu horisontal ✓✓