Tolong bantu yah…..

A]
∠BOC dan ∠COD saling berpenyiku, sehingga :
∠BOC + ∠COD = 90°
3x – 5 + 2x – 5 = 90
5x – 10 = 90
5x = 90 + 10
5x = 100
x = 100 / 5
x = 20

b]
∠BOC = 2x – 5
            = 2(20) – 5
            = 40 – 5
             = 35°

c]
∠COD = 3x – 5
            = 3(20) – 5
            = 60 – 5
            = 55°

A.) nilai x
3x – 5 + 2x – 5 = 90°
5x = 100°
x = 20°

b.) sudut BOC
2x – 5
= 2 (20°) – 5
= 40° – 5
= 35°

c.) sudut COD
3x – 5
= 3 (20°) – 5
= 60° – 5
= 55°

semoga bermanfaat 🙂