Tolong bantu yak kakak. Dijawab sama caranya

Tolong bantu yak kakak. Dijawab sama caranya

$| {x}^{2} - 2x - 1 | < 2 \ - 2 < {x}^{2} - 2x - 1 < 2 \ \ {x}^{2} - 2x - 1 > - 2 \ {x}^{2} - 2x + 1 > 0 \ {(x - 1)}^{2} > 0 \ |x - 1| > 0 \ x - 1 > 0 : atau : x - 1 < 0 \ x > 1 : atau : x < 1 \ \ {x}^{2} - 2x - 1 < 2 \ {x}^{2} - 2x - 3 < 0 \ (x - 3)(x + 1) < 0 \ x - 3 = 0 : atau : x + 1 = 0 \ -1 < x < 3 \ \ 1 < x < 3 : dan : -1< x < 1$