Tolong bantuan nya tapi pakai jalan trimakasih

By Posted on

Tolong bantuan nya tapi pakai jalan trimakasih

Tolong bantuan nya tapi pakai jalan
trimakasih

Jawaban Terkonfirmasi

1.
displaystyle lim_{xto1}frac{x-1}{1-sqrt{x}}\lim_{xto1}frac{x-1}{1-sqrt{x}}timesfrac{1+sqrt{x}}{1+sqrt{x}}\lim_{xto1}frac{(x-1)(1+sqrt{x})}{1^2-sqrt{x}^2}\lim_{xto1}frac{(x-1)(1+sqrt{x})}{1-x}\lim_{xto1}frac{-(1+sqrt{x})}{1}\lim_{xto1}-(1+sqrt{x})\\-(1+sqrt{1})\-(2)\boxed{boxed{-2}}

2.
displaystyle lim_{xto3}frac{sqrt{x+4}-sqrt{2x+1}}{x-3}\lim_{xto3}frac{sqrt{x+4}-sqrt{2x+1}}{x-3}timesfrac{sqrt{x+4}+sqrt{2x+1}}{sqrt{x+4}+sqrt{2x+1}}\lim_{xto3}frac{(sqrt{x+4})^2-(sqrt{2x+1})^2}{(x-3)(sqrt{x+4}+sqrt{2x+1})}\lim_{xto3}frac{(x+4)-(2x+1)}{(x-3)(sqrt{x+4}+sqrt{2x+1})}\lim_{xto3}frac{x+4-2x-1}{(x-3)(sqrt{x+4}+sqrt{2x+1})}\lim_{xto3}frac{3-x}{(x-3)(sqrt{x+4}+sqrt{2x+1})}\lim_{xto3}frac{-1}{sqrt{x+4}+sqrt{2x+1}}

displaystyle frac{-1}{sqrt{3+4}+sqrt{2(3)+1}}\frac{-1}{sqrt{7}+sqrt{7}}\frac{-1}{2sqrt{7}}\boxed{boxed{-frac{1}{14}sqrt{7}}}

3.
displaystyle lim_{xto0}frac{2x^2+3x}{x}\lim_{xto0}frac{x(2x+3)}{x}\lim_{xto0}2x+3\\2(0)+3\boxed{boxed{3}}

4.
displaystyle intfrac{2}{xsqrt{x}},dx\2intfrac{1}{x^{frac{3}{2}}},dx\2int x^{-frac{3}{2}},dx\2(frac{1}{-frac{3}{2}+1} x^{-frac{3}{2}+1})+C\2(frac{1}{-frac{1}{2}} x^{-frac{1}{2}})+C\2(-2frac{1}{sqrt{x}})+C\boxed{boxed{-frac{4}{sqrt{x}}+C}}