Tolong bantuannya....

Tolong bantuannya….

limit substitusi
rasional bentuk akar

Penjelasan dengan langkah-langkah:

$sf lim _{xto5} dfrac{sqrt{x + 2sqrt{x+1}}}{sqrt{x- 2sqrt{x+1}}}$

subs x = 5

$sf lim _{xto5} dfrac{sqrt{5 + 2sqrt{5+1}}}{sqrt{5- 2sqrt{5+1}}}$

$sf lim _{xto5} dfrac{sqrt{5 + 2sqrt{6}}}{sqrt{5- 2sqrt{6}}}$

$sf lim _{xto5} dfrac{sqrt{(sqrt3 + sqrt 2)^2}}{sqrt{(sqrt 3 - sqrt 2)^2}}$

$sf lim_{xto 5} dfrac{sqrt 3 + sqrt 2}{sqrt 3 - sqrt 2} . . .kali akar sekawan$

$sf lim_{xto 5} dfrac{(sqrt 3 + sqrt 2)(sqrt 3+sqrt2)}{(sqrt 3 - sqrt 2)(sqrt3 + sqrt 2)}$

$sf lim_{xto 5} dfrac{ 3 + 2 + 2sqrt 6}{3-2}$

$sf lim_{xto 5} dfrac{5 + 2sqrt 6}{1}$

$sf = 5 + 2sqrt 6$

limit tentu

cara lain

soal

= lim x→5 √[(x + 2√(x + 1))/(x – 2√(x + 1))]

kalikan pembilang dan penyebut dg (x + 2√(x + 1))

= lim x→5 √[(x + 2√(x + 1))² / (x² – 4(x + 1))]

= √[(5 + 2√(5 + 1))² / (5² – 4(5 + 1))]

= √[(5 + 2√6)² / (25 – 24)]

= 5 + 2√6