Tolong bantuu kaaaakk

Jawab:

1. 18 cm

2. 12 cm

Penjelasan dengan langkah-langkah:

Nomor 1

Jarak E ke P = EP

= √(½CG²) + (s√2)²)

= √(6² + (12√2)²)

= √(36 + 288)

= √324

= 18

Jadi jarak E ke P = 18cm

Nomor 2

Jarak A ke diagonal CE

= AE × AC : CE

= 20 × √(12²+9²) : √(12²+9²+20²)

= 20 × √(144 + 81) : √(144 + 81 + 400)

= 20 × √(225) : √(625)

= 20 × 15 : 25

= 20 × 3 : 5

= 4 × 3

= 12

Jadi jarak A ke diagonal CE = 12cm

Semoga Bermanfaat ^_^

1.

PG = 1/2 CG = 6 cm

EG = diagonal sisi = 12√2 cm

EP² = EG² + PG²

EP² = (12√2)² + 6²

EP² = 288 + 36

EP² = 324

EP = √324

EP = 18 cm

2.

AC² = AB² + BC²

AC² = 12² + 9²

AC² = 144 + 81

AC² = 225

AC = 15 cm

AE = CG = 20 cm

CE² = AC² + AE²

CE² = 15² + 20²

CE² = 225 + 400

CE² = 625

CE = 25 cm

Jarak A ke CE (misal AP)

AP x CE = AC x AE

AP x 25 = 15 x 20

25 AP = 300

AP = 300/25

AP = 12 cm