Tolong carikan luas segitiga ABC (pakai cara ya kak)

AC = b = 6√6 cm

<A = 60°, <B = 45°

<C = 180° – (60° + 45°)

<C = 180° – 105°

<C = 75°

Luas ABC = b².sin A.sin C / 2.sin B

= (6√6)².sin 60° . sin 75° / 2.sin 45°

= 216 . √3/2 . (√6+√2) / 4 : 2.√2/2

= 81√2 + 27√6 : √2

= 81 + 27√3 cm²

= 127,77 cm²