Tolong dengan caranya kaka

#F

∫ a xⁿ dx = a /(n +1) xⁿ⁺¹

1a) ∫(12x – 4)² dx = ∫ (144 x² – 96 x + 16) dx

= 144 (¹/₃ ) x³ -96 (¹/₂) x² + 16 x + c

= 48x³ – 48 x² + 16x + c

1b) ∫(x+2)(x + 1) dx = ∫ (x² + 3x + 1) dx

= ¹/₃ x³ + 3 (¹/₂) x² + x + c

= ¹/₃ x³ + ³/₂ x² + x + c

1c) ∫(10x + 6x² +12x³) dx

= 10 (¹/₂) x² + 6 (¹/₃) x³ + 12 (¹/₄) x⁴ + c

= 5x² + 2x³ + 3x⁴ + c